Daer Wien users, I'm trying to calculate the possible low-spin and high-spin states of La0.75Sr0.25CoO3 compound. In order to define the Low spin , I modified the case.inst file so the up and down spin of Co d-orbitals are equal, also for the case of high spin I put the maximum number of unpaired electrons. See the files below: Low spin ---------- Co Ar 3 3, 2,2.0 N 3, 2,2.0 N 3,-3,1.5 N 3,-3,1.5 N 4,-1,1.0 N 4,-1,1.0 N
High Spin ---------------- Co Ar 3 3, 2,2.0 N 3, 2,2.0 N 3,-3,3.0 N 3,-3,0.0 N 4,-1,1.0 N 4,-1,1.0 N But In both cases I got a moment of 3.14 mb on the Co atom. So what do you think is wrong, here? Thanks in advance Bothina
Stefaan
Use runsp_c_lapw to obtain the non-magnetic solution (or runfsm -m xxx
when you want a low-moment FM state).Defining just different starting configuration may or may not lead to a
desired self-consistent solution. This depends on the particular system
and the way the scf-cycle proceeds.
Reference: https://www.mail-archive.com/wien@zeus.theochem.tuwien.ac.at/msg00656.html
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